Answer:
a.) 1.23 seconds
b.) 14 m/s
Step-by-step explanation:
a.) Before commencing the calculation, we need to specify the information.
Data:
acceleration dues to gravity, g = 9.81 m/s²
initial velocity u = 2.0 m/s
height, s = 40 m
t = ?
The formula for finding the distance is s = ut + 1/2at²
Therefore, 40 = 2t + 1/2×(9.81) ×t²
80 = 4t + 9.81 t²
Solving for t by the quadratic equation gives t = 1.23 s [Note the other negative value for t is rejected because there is no negative time]
b) The final velocity is given by the following equation:
v = u + at
where v = final velocity just before the camera lands on the ground
u = initial velocity
t = time taken
a = g = acceleration dues to gravity = 9.81 m/s²
Calculating gives
v = 2 + 9.81×1.23
= 14 m/s Ans
