Answer:
Tension in the string will be 19.293 N
Explanation:
We have given length of the string r = 42.1 cm = 0.421 m
Mass of the stone m = 1000 gram
We know that 1000 gram = 1 kg
Velocity in the circular path v = 2.85 m/sec
We have to find the tension in the string
Tension in the string will be equal to centripetal force
So tension [tex]T=\frac{mv^2}{r}[/tex], here m is mass, v is velocity and r is length of the string
So tension in the string [tex]T=\frac{1\times 2.85^2}{0.421}=19.293N[/tex]
So tension in the string will be equal to 19.293 N
