In hydrogen, the transition from level 2 to level 1 has a rest wavelength of 121.6 nm. Suppose you see this line at a wavelength of 120.5 nm in Star A, at 121.2 nm in Star B, at 121.9 nm in Star C, and at 122.9 nm in Star D. a. Which of these stars are coming toward us? And which ones are moving away?
b. Which star is moving fastest relative to us?

Respuesta :

Answer:

Explanation:

Given Data:

rest wavelength = λ₀=121.6nm

Star A wavelength = λa=120.5nm

Star B wavelength = λb=121.2nm

Star C wavelength = λc=121.9nm

Star D wavelength = λd=122.9nm

According to Doppler shift formula,

we have

     v/c=(λ-λ₀)/λ₀

As we know c=speed of light=3*10^8m/s⁻¹

a.

Star A: v=(120.5-121.6)(3*10^8)/121.6 = -2.71*10^6m/s(towards)

Star B: v=(121.2-121.6)(3*10^8)/121.6 = -9.87*10^5m/s(towards)

Star C: v=(121.9-121.6)(3*10^8)/121.6 = 7.40*10^5m/s(away)

Star D: v=(122.9-121.6)(3*10^8)/121.6 = 3.21*10^6m/s(away)

b.

Star D is moving fastest relative to us.

Star A & B are coming toward us while Star C & D are moving away from us.

The Star D is the star that is moving fastest relative to us.

Given Data

Rest wavelength = λ₀=121.6nm

Star A wavelength = λa=120.5nm

Star B wavelength = λb=121.2nm

Star C wavelength = λc=121.9nm

Star D wavelength = λd=122.9nm

According to Doppler shift formula, we have v/c=(λ-λ₀)/λ₀

Generally, C= Speed of light = 3*10^8m/s⁻¹

Question A

Star A: v=(120.5-121.6)(3*10^8)/121.6

Star A = -2.71*10^6m/s(towards)

Star B: v=(121.2-121.6)(3*10^8)/121.6

Star B = -9.87*10^5m/s(towards)

Star C: v=(121.9-121.6)(3*10^8)/121.6

Star C= 7.40*10^5m/s(away)

Star D: v=(122.9-121.6)(3*10^8)/121.6

Star D = 3.21*10^6m/s(away)

b. The Star D is the star that is moving fastest relative to us.

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