Respuesta :
Answer:
5650 g/mol
Explanation:
The osmotic pressure (π) is the pressure needed to prevent that the osmose occur in a system. Osmose is the process that a solvent goes through a membrane where the solution is more concentrated.
This property can be calculated by:
π = M*R*T
Where M is the molarity of the solution (mol/L), R is the ideal gas gas constant (62.3 torr.L/mol.K), and T is the temperature (25°C = 298 K), so:
23 = M*62.3*298
M = 1.24x10⁻³ mol/L
So, if the concentration is mass is 7.0 g/L, the molar mass (MM) of the sugar is its concentration is mass divided by the molarity:
MM = 7/1.24x10⁻³
MM = 5650 g/mol
5650 g/mole is the molar mass of the given sugar, whose osmotic pressure of solution is is the molar mass of this sugar.
What is osmotic pressure?
It is that pressure which is applied on the solution to stop the flow of pure solvent from low concentration to high concentration through semipermeable membrane, and it is calculated as follow:
π = CRT, where
π = osmotic pressure = 23 torr (given)
C= concentration = to find?
R = ideal gas gas constant = 62.3 torr.L/mol.K
T = temperature = 25 degree C = 298 K
Putting all these value in the above equation, we get
23 = C × 62.3 × 298
C = 1.24x10⁻³ mol/L
Here the concentration is given in the form of molarity, which defines as no. of moles of solute present in per liter of solvent. And no. of moles is calculated as :
n = W/M, where
W = given mass = 7.0 g (given)
M = molar mass = to find?
n = no. of moles = 1.24x10⁻³ mol/L (calculated above)
Putting all values in above equation we get,
M = 7/1.24x10⁻³ = 5650 g/mol.
Hence, 5650 g/mol is the molar mass of this given sugar.
To learn more about osmotic pressure, visit the below link:
https://brainly.com/question/25904085
