Answer:
2930.90 ft
Explanation:
*Attached are two rough sketches I made to represent the problem.
In diagram 2, the bearings are represented relative to the boat's position.
To find x, the distance between the boat and point having bearing 110° to the boat, we can use sine rule:
(sin 10°) / 550 = (sin 100) / x
=> x = (550 * sin 100°) / sin 10°
x = 3119 ft
Having found this, we can now find the distance between the host and the shore, as represented in diagram 1.
Using trigonometric function of SOHCAHTOA, we have that:
cos 20° = y / 3119
=> y = 3119 * cos 20°
y = 2930.90 ft
Hence, the distance between the boat and the shore is 2930.90 ft
