Answer:
284.88 grams of CO₂
Explanation:
Data Given:
Volume = V = 145 L
Standard Temperature = T = 273.15 K
Standard Pressure = P = 1 atm
Universal Gas Constant = R = 0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹
Moles = n = ??
Formula Used:
Assuming that the CO₂ gas is acting ideally we will apply Ideal Gas equation;
P V = n R T
Solving for n,
n = P V / R T
Putting values,
n = 1 atm × 145 L / 0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹ × 273.15 K
n = 6.47 mol
Secondly, Moles are converted to Mass as;
Moles = Mass / M.Mass
Solving for Mass,
Mass = Moles × M.Mass
Mass = 6.47 mol × 44.01 g/mol
Mass = 284.88 grams of CO₂
