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A car of mass m push = 1200 kg is capable of a maximum acceleration of 6.00 m / s 2 . If this car is required to push a stalled car of mass m stall = 1750 kg, what is the maximum magnitude of the acceleration a of the two‑car system? a = 0.62 m / s 2

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cjmejiab

1)

first you find the maxium force that the car can produce.

f=ma

Fmax=(1100kg)(6m/s^2)

then use f = ma again to find the accel with the passengers

Fmax=(1100kg +1650kg)(a)

=> a = (1100kg)(6m/s^2)/( 1100kg +1650kg)

= 2.4 m/s^2

snehashish65

The maximum magnitude of the acceleration of the two‑car system is  [tex]2.44 \;\rm m/s^{2}[/tex].

Given data:

The mass of car is, m = 1200 kg.

The maximum acceleration is, [tex]a =6.00 \;\rm m/s^{2}[/tex].

The mass of stall is, m' = 1750 kg.

As per the Newton's Second law of motion, the applied force on the car is equal to the product of mass and acceleration of car. So, the maximum force to push the car is given as,

F = ma

[tex]F = 1200 \times 6.00\\\\F= 7200\;\rm N[/tex]

Now for two-car system, the total mass is,

M = m + m'

M = 1200 +1750 = 2950 kg.

So, the acceleration for the two-car system is,

[tex]F = M \times a'\\\\7200 =2950 \times a'\\\\a'=2.44 \;\rm m/s^{2}[/tex]

Thus, the maximum magnitude of the acceleration a of the two‑car system is  [tex]2.44 \;\rm m/s^{2}[/tex].

Learn more about the Newton's Second law here:

https://brainly.com/question/13447525

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