Answer : The volume of the second tank is, [tex]4ft^3[/tex]
Explanation :
Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.
[tex]P\propto \frac{1}{V}[/tex]
or,
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 2 atm
[tex]P_2[/tex] = final pressure of gas = 1 atm
[tex]V_1[/tex] = initial volume of gas = [tex]2ft^3[/tex]
[tex]V_2[/tex] = final volume of gas = ?
Now put all the given values in the above equation, we get:
[tex]2atm\times 2ft^3=1atm\times V_2[/tex]
[tex]V_2=4ft^3[/tex]
Therefore, the volume of the second tank is, [tex]4ft^3[/tex]
