A stone is dropped into a lake, creating a circular ripple that travels outward at a speed of 35 cm/s.
Express the radius r of this circle as a function of the time t (in seconds).

Respuesta :

Answer:

The radius r of this circle as a function of the time t :

[tex]r(t)=35\times t[/tex]

Step-by-step explanation:

Speed of the circular ripple = S = 35 cm/s

Radius of the ripple at time t = r

[tex]Speed=\frac{Distance}{Time} [/tex]

[tex]35cm/s=\frac{r}{t}[/tex]

[tex]r=35 cm/s \times t[/tex]

The radius r of this circle as a function of the time t :

[tex]r(t)=35\times t[/tex]

The radius r of this circle is a function of the time t (in seconds) is 35t.

Given that

A stone is dropped into a lake, creating a circular ripple that travels outward at a speed of 35 cm/s.

We have to determine

The radius r of this circle is a function of the time t (in seconds).

According to the question

Speed of the circular ripple = S = 35 cm/s

Radius of the ripple at time t = r

Then

The radius r of this circle is a function of the time t (in seconds) is determined by the following formula;

[tex]\rm Speed = \dfrac{Distance}{Time}[/tex]

Substitute all the values in the formula;

[tex]\rm Speed = \dfrac{Distance}{Time}\\ \\ 35 = \dfrac{r}{t}\\ \\ r = 35 \times t\\ \\ r = 35t[/tex]

Hence, The radius r of this circle is a function of the time t (in seconds) is 35t.

To know more about the Distance formula click the link given below.

https://brainly.com/question/2094864

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