Answer: C₃H₈
Explanation:
From PV = nRT
Moles of CO2 = PV / RT =(1 x 1.037)/(0.08206 x ( 273+98.3)) = 0.0340 moles of CO2
CxHy + (x + (y/2))O₂ ----> xCO₂ + yH₂O
there is 1 mole of C in each mole of CO2 so moles of C in CO₂ = 0.0340 moles
mass of C in CO₂ = 0.0340 x 12 = 0.41 g
This means mass of C in the hydrocarbon = 0.41g
so mass of H in the hydrocarbon = 0.50 - 0.41= 0.09 g
moles of H in the hydrocarbon = mass/molar mass = 0.09/1 = 0.09 moles
molar ratio of C:H = 0.034 : 0.09 = 1 :2.67
or 3 :8
empirical formula is C3H8
