Step-by-step explanation:
Equation of given line is:
[tex]y = \frac{2}{5} x + 1 \\ equating\: it \: with \: y = m_1x + c, \:we\:find \\ slope \: of \: given \: line \: (m_1 )= \frac{2}{5} \\ y - intercept \: (c) = 1 \\ let \: the \: slope \: of \: required \: line \: be \: m_2. \\ \therefore \: m_1 \times m_2 = - 1..( \because \: lines \: are \: \perp) \\ \therefore \: \frac{2}{5} \times m_2 = - 1 \\ \therefore \:m_2 = - \frac{5}{2} \\ \\ equation \: of \: required \: line \: in \: slope \: \\intercept \: form \: is \: given \: as: \\ y = m_2x + c \\ \huge \orange{ \boxed{\therefore \: y =- \frac{5}{2}x + 1}} \\ [/tex]
