Respuesta :
eliminating y
x + y = 4 .......... x 2
3x - 2y = 7 ...... x 1
2x + 2y = 8
3x - 2y = 7
_________ +
5x = 15
x = 3
substitute
x + y = 4
3 + y = 4
y = 1
.
.
x = 3 and y = 1
eliminating y
x + y = 4 .......... x 2
3x - 2y = 7 ...... x 1
2x + 2y = 8
3x - 2y = 7
_________ +
5x = 15
x = 3
substitute
x + y = 4
3 + y = 4
y = 1
.
.
x = 3 and y = 1