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4) Consider a separate rocket, also in deep space with a mass of 30.0 kg. If the rocket is
observed to be travelling at v = 5.00m/s at t = 3.00 s and then travelling at v= -2.00m/s at t = 14.0 s
with constant acceleration, calculate:
a) the acceleration, à.
b) the force F, acting on the rocket from the thrusters.

Respuesta :

MathPhys

Explanation:

a) Acceleration is the change in velocity over change in time.

a = Δv / Δt

a = (-2.00 m/s − 5.00 m/s) / (14.0 s − 3.00 s)

a = -7/11 m/s²

a ≈ -0.636 m/s²

b) Force is mass times acceleration.

F = ma

F = (30.0 kg) (-0.636 m/s²)

F = -19.1 N

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