To solve this problem we will apply the principle of conservation of energy and the definition of kinematic energy as half the product between mass and squared velocity. So,
[tex]KE_i = KE_f[/tex]
[tex]KE_f = \frac{1}{2} mv^2[/tex]
Here,
m = Mass
V = Velocity
Replacing,
[tex]KE_f = \frac{1}{2} (12000)(11)^2[/tex]
[tex]KE_f = 72600J[/tex]
Therefore the final kinetic energy of the two car system is 72.6kJ
The final kinetic energy of two car system is 72,600 Joules.
To understand more, check below explanation.
The energy is neither be created nor be destroyed only transfer from one form to another form.
So that,
Initial kinetic energy = Final kinetic energy
It is given that, mass,m = 1200kg , speed, v = 11m/s.
As we know that,
Kinetic energy[tex]=\frac{1}{2}*m*v^{2}[/tex]
Substute above values in above formula.
[tex]K.E=\frac{1}{2}*1200*(11)^{2} \\\\K.E=600*121=72,600J[/tex]
Hence, the final kinetic energy of two car system is 72,600 Joules.
Learn more about the kinetic energy here:
https://brainly.com/question/25959744
