ASAP PLEASE ANSWER THIS WILL GIVE BRAINLIEST

The rectangle shown has a perimeter of 86 cm and the given area. Its length is 7 more than three times its width. Write and solve a system of equations to find the dimensions of the rectangle.

A= 306cm squared
A is the rectangle

Respuesta :

Answer:

Therefore,

The Dimensions are,

[tex]Length = 34\ cm\\\\Width = 9\ cm[/tex]

Step-by-step explanation:

Given:

Perimeter of a rectangle,

Perimeter = 86 cm

let "x" be the width of rectangle,

Width = x

then according to the given condition,

length will be given as,

[tex]Length = 3x+7[/tex]

To Find:

Length =?

Width =?

Solution:

Perimeter of rectangle is given by,

[tex]\textrm{Perimeter of Rectangle}=2(Length+Width)[/tex]

Substituting the values we get

[tex]86=2(3x+7+x)\\\\86=2(4x+7).........Equation\\\\86=8x+14\\\\8x=86-14=72\\\\x=\dfrac{72}{8}=9\ cm[/tex]

Substituting "x" in Length we get

[tex]Length = 3\times 9 +7=34[/tex]

Also Area Of Rectangle is given by

[tex]\textrm{Areaof Rectangle}=(Length\times Width)=34\times 9=306\ cm^{2}[/tex]

Therefore,

The Dimensions are,

[tex]Length = 34\ cm\\\\Width = 9\ cm[/tex]

Q&A Education