Explanation:
We are given with compound C₆N₄O₁₀: mass percentage of all is :
For C = 12 x 6 /288=0.25%
For N= 14 x 4 /288=0.19%
For 0= 16 x 10/288=0.5%
The elements present are :
Atomic mass moles Simplest ratio rounding off
C 12 0.25/12=0.020 0.02/0.02=1 2
N 14 0.9/14=0.06 0.06/0.02=3 6
O 16 0.5/16=0.03 0.03/0.02=1.5 3
The empirical formula derived is : C₂n₆O₃
