Answer : The volume of the tank is, 1.54 mL
Explanation :
To calculate the volume of gas we are using ideal gas equation:
[tex]PV=nRT\\\\PV=\frac{w}{M}RT[/tex]
where,
P = pressure of gas = 300 kPa = 2.96 atm
Conversion used : (1 atm = 101.325 kPa)
V = volume of gas = ?
T = temperature of gas = [tex]77^oC=273+77=350K[/tex]
R = gas constant = 0.0821 L.atm/mole.K
w = mass of gas = 4.6 kg = 4600 g
M = molar mass of air = 28.96 g/mole
Now put all the given values in the ideal gas equation, we get:
[tex](2.96atm)\times V=\frac{4600g}{28.96g/mole}\times (0.0821L.atm/mole.K)\times (350K)[/tex]
[tex]V=1541.98L=1.54mL[/tex] (1 L = 1000 mL)
Therefore, the volume of the tank is, 1.54 mL
