Respuesta :
Answer: The molarity of saline solution is 0.909 M
Explanation:
We are given:
5.21 w/w % NaCl
This means that 5.21 grams of NaCl is present in 100 grams of solution
To calculate mass of a substance, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
Density of solution = 1.02 g/mL
Mass of solution = 100 g
Putting values in above equation, we get:
[tex]1.02g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.02g/mL}=98.04mL[/tex]
To calculate the moalrity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
Given mass of NaCl = 5.21 g
Molar mass of NaCl = 58.44 g/mol
Volume of solution = 98.04 mL
Putting values in above equation, we get:
[tex]\text{Molarity of solution}=\frac{5.21\times 1000}{58.44g/mol\times 98.04}\\\\\text{Molarity of solution}=0.909M[/tex]
Hence, the molarity of saline solution is 0.909 M
