Answer:
(C) 16
Explanation:
Given:
The amplitude of first wave (s₁) = 20 mm
The amplitude of second wave (s₂) = 5 mm
Intensity of first wave = Iₓ
Intensity of second wave = [tex]I_y[/tex]
The intensity associated with a wave depends on the amplitude of the wave.
The intensity (I) is directly proportional to the square of the amplitude (s) of the wave and is expressed as:
[tex]I=ks^2\\Where\ k\to constant\ of\ proportionality[/tex]
Now, the intensities of the two waves are given as:
[tex]I_x=ks_1^2=k(20)^2\\\\I_y=ks_2^2=k(5)^2[/tex]
Dividing both the intensities, we get:
[tex]\frac{I_x}{I_y}=\frac{k(20)^2}{k(5)^2}\\\\\frac{I_x}{I_y}=\frac{400}{25}\\\\\frac{I_x}{I_y}=16[/tex]
Therefore, the option (C) is correct.
