Amplitude of oscillation is 0.33 m
Explanation:
Amplitude is the maximum displacement of points on a wave from the point of equilibrium. In the above question,mass attached to a spring of k=18.9N/m follows an oscillatory motion where ,
Angular frequency = [tex]\sqrt{k/m}[/tex] where k is the spring constant and m is the mass
Angular frequency =[tex]\sqrt{18.9/.250[/tex] = 8.69
Therefore ,amplitude is equal to velocity/angular velocity
A=2.89/8.69
=0.33m
Hence , the amplitude of oscillation is 0.33 m.
