Find the equivalent resistance between points A and B shown in the figure(Figure 1). Consider R1 = 1.9 Ω , R2 = 2.5 Ω , R3 = 4.4 Ω , R4 = 3.5 Ω , R5 = 5.5 Ω , and R6 = 7.1 Ω .

The resistor can be defined as a device that has some electrical resistance and that is used in an electric circuit for protection, operation, or current control.

Given that there are 6 resistors connected in-between points A and B as shown in the attachment.

R1 = 1.9 Ω, R2 = 2.5 Ω, R3 = 4.4 Ω, R4 = 3.5 Ω, R5 = 5.5 Ω, and R6 = 7.1 Ω.

The resistors R3, R4, and R5 are in parallel connections. Let's consider that R' is the equivalent resistor of this parallel connection, then,

[tex]\dfrac {1}{R'} =\dfrac {1}{R_3} + \dfrac {1}{R_4}+\dfrac {1}{R_5}[/tex]

[tex]\dfrac {1}{R'}= \dfrac {1}{4.4}+ \dfrac {1}{3.5}+\dfrac {1}{5.5}[/tex]

[tex]\dfrac {1}{R'}= 0.69[/tex]

[tex]R' = 1.45[/tex]

The equivalent resistor is in series connection with R6. Hence, the equivalent resistance R'' is given below.

[tex]R'' = R' + R_6[/tex]

[tex]R'' = 1.45 + 7.1[/tex]

[tex]R'' = 8.55[/tex]

Now the resistors R1, R2, and R'' are in parallel connection, so the equivalent resistor R is given as,

[tex]\dfrac {1}{R} = \dfrac {1}{R_1} + \dfrac {1}{R_2} + \dfrac {1}{R''}[/tex]

[tex]\dfrac {1}{R} = \dfrac {1}{1.9} +\dfrac {1}{2.5} +\dfrac {1}{8.55}[/tex]

[tex]\dfrac {1}{R} = 1.043[/tex]

[tex]R = 0.958[/tex]

Hence we can conclude that the equivalent resistance of the circuit shown in the attachment is 0.958 Ω.

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