Answer:
B. 66.4 V
Explanation:
for a Y-Y connection (star connection), the relationship between the line voltages and the phase voltages is governed by the formula:
[tex]V_{L} = \sqrt{3} (V_{ph})[/tex]
Where [tex]V_{L}[/tex] = Line Voltage = 115 V (AC there just shows that the current is alternating current )
and [tex]V_{ph}[/tex] = Phase Voltage
⇒ [tex]V_{ph}[/tex] = [tex]V_{L}[/tex] / [tex]\sqrt{3}[/tex]
[tex]V_{ph}[/tex] = 115 / [tex]\sqrt{3}[/tex]
[tex]V_{ph}[/tex] = 66.4 V
Hence the secondary Line to neutral voltage is 66.4 Volts
The secondary line to neutral voltage is Option B 66.4 V.
Given that,
Based on the above information, the calculation is as follows:
[tex]V_{ph} = V_L \div \sqrt{3}\\\\= 115 \div \sqrt{3}[/tex]
= 66.4 V
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