Answer:
[tex]2.7\times 10^{12}[/tex]
Explanation:
We are given that
Electric field =[tex]E=152N/C[/tex]
We have to find the ratio of magnitude of the upward electric force on an electron to the magnitude of gravitational force on the electron.
We know that
F=qE
Charge on an electron,q=[tex]1.6\times 10^{-19}C[/tex]
Using the formula
Upward electric force=[tex]152\times 1.6\times 10^{-19}[/tex] N
Upward electric force=[tex]F_e=2.43\times 10^{-17}[/tex] N
Mass of electron=[tex]m_e=9.1\times 10^{-31} kg[/tex]
[tex]g=9.8m/s^2[/tex]
Gravitational force=[tex]F=mg[/tex]
Using the formula
Gravitational force=[tex]F_g=9.1\times 10^{-31}\times 9.8=8.92\times 10^{-30} N[/tex]
Ratio of Fe to the Fg=[tex]\frac{2.43\times 10^{-17}}{8.92\times 10^{-30}}[/tex]
[tex]\frac{F_e}{F_g}=2.7\times 10^{12}[/tex]
