There are 20 dimes and 80 quarters
Solution:
Let "d" be the number of dimes
Let "q" be the number of quarters
1 dime = $ 0.10
1 quarter = $ 0.25
Panchito Pantera has 100 coins
Therefore,
number of dimes + number of quarters = 100
d + q = 100 ----------- eqn 1
He has a total of $22. Thus we frame a equation as:
number of dimes x 0.10 + number of quarters x 0.25 = 22
[tex]d \times 0.10 + q \times 0.25 = 22[/tex]
0.1d + 0.25q = 22 --------- eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
d = 100 - q ------- eqn 3
Substitute eqn 3 in eqn 2
0.1(100 - q) + 0.25q = 22
10 - 0.1q + 0.25q = 22
0.15q = 22 - 10
0.15q = 12
Divide both sides by 0.15
q = 80
Substitute q = 80 in eqn 3
d = 100 - 80
d = 20
Thus there are 20 dimes and 80 quarters
