Answer:
θ = 30⁰
Explanation:
We have been given two wave displacement equations,
[tex]y_{1} =2sin\theta +1[/tex] ........(1)
[tex]y_{2}=3sin\theta +0.5[/tex] ........(2)
The waves will have same displacements when [tex]y_{1}=y_{2}=y[/tex] (say)
Therefore, operating (2) - (1), we get,
[tex]sin\theta - 0.5=0[/tex]
or, [tex]\theta = sin^{-1}(0.5)=30^{o}[/tex] (since, sin 30⁰ = 0.5)
We can check the answer by putting [tex]\theta=30^{o}[/tex] in equations (1) and (2),
[tex]y_{1}=2sin30^{o}+1=2\times0.5 + 1= 2[/tex]
[tex]y_{2}=3sin30^{o}+0.5=3\times0.5+0.5=1.5+0.5=2[/tex]
Answer:
θ= 30°
Explanation:
Set the wave functions equal to another, as displacements would be the same. Therefore, 2sin θ+1 = 3sin θ+.5.
sin θ=.5
θ= 30°
