Urgent!
Write a polynomial, P(x), in factored form given the following requirements.

Degree: 3
Zeros (roots) at (−2,0) with multiplicity 2 and (3,0) with multiplicity 1
P(x) passes through the point (2,80)

Respuesta :

Answer:

The polynomial will be P(x) = - 5 (x + 2)²(x - 3)

Step-by-step explanation:

The degree of the polynomial P(x) is 3 and it has zeros at x = - 2 with multiplicity 2 and at x = 3 with multiplicity 1.

Therefore, (x + 2)² and (x - 3) are the factors of the equation.

Let the polynomial is

P(x) = a(x + 2)²(x - 3) ........... (1)

Now, the polynomial passes through the point (2,80).

So, from equation (1) we gat,

80 = a(4)²(-1)

a = - 5

Therefore, the polynomial will be P(x) = - 5 (x + 2)²(x - 3) (Answer)

The required polynomial is [tex]P(x) = - 5 (x + 2)^{2} (x - 3)[/tex]

Any polynomial have number of roots equal to its degree of polynomial.

Since, the degree of the polynomial P(x) is 3. it means that it has 3 roots.

it has zeros at x = - 2 with multiplicity 2, it means that factor (x - 2) have power 2 and at x = 3 with multiplicity 1 means that factor (x - 3) have power of 1 .

Thus, [tex](x + 2)^{2}[/tex] and (x - 3) are the factors of the equation.

Let us consider the polynomial is [tex]P(x) = k(x + 2)^{2} (x - 3) .[/tex]

Since,  the polynomial passes through the point (2,80).

So, substituting point (2, 80)  in above polynomial equation.

   We get,   [tex]80 = a(4)^{2} (-1)[/tex]

                      a = - 5

Therefore, the polynomial is [tex]P(x) = -5(x + 2)^{2} (x - 3) .[/tex]

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