You take a bucket outside and hold it as you normally would to hold water. As the rain comes down, the flux of water out of the bucket is Incorrect: Your answer is incorrect. . If you were to then cut out the bottom of the bucket and again hold it in the rain, the flux of water out of the bucket would be (postive, negative, zero) ?

Respuesta :

Answer:

  • the bucket-surface area vector and the direction of the rain is 180° which gives a negative flux in the outward direction.
  • If we cut the base of the bucket then hold it in the rain then the there is no area intercepted by the rainfall and hence we have a zero flux.

Explanation:

We know that flux is defined as the density of any energy field passing through a given area parallel to the area vector.

Mathematically:

[tex]\phi=\bar E.A\cos\theta[/tex]

where:

[tex]\phi=[/tex] flux through the area

[tex]A=[/tex] area of concern

[tex]\bar E=[/tex] density of energy field per unit area

[tex]\theta=[/tex] angle between the energy field lines and the normal to area.

When we hold a bucket in the rain then assuming that the base of the bucket is normal to the direction of rainfall then the angle between the area vector and the rain drop is zero when observed from inside.

  • For the flux outside the bucket we are concerned with the outer surface of the bucket, now the angle formed between the bucket-surface area vector and the direction of the rain is 180° which gives a negative flux in the outward direction.
  • If we cut the base of the bucket then hold it in the rain then the there is no area intercepted by the rainfall and hence we have a zero flux.

The angle between the raindrops and the surface area of the bucket is 180 degrees. Hence the flux will be negative and in the outward direction of the bucket.

The value of flux will be zero when the base of the bucket has been cut and then hold in rain.

Electric flux

The electric flux can be defined as the property of an electric field that shows the number of electric field lines intersecting a given area.

The electric flux can be written in an equation form as given below.

[tex]\phi = EA cos\theta[/tex]

Where [tex]\phi[/tex] is the electric flux, E is the electric field, A is the area of surface and [tex]\theta[/tex] is the angle between the electric field lines and the normal (perpendicular) to A.

Let us consider that the base of the bucket is normal to the direction of the rainfall when we hold the bucket in rain. In this case, the angle between the raindrops and the normal to the surface will be zero inside the bucket.

From the outer surface, the angle formed between the surface area of the bucket and the direction of the rain is 180 degrees. When we put the value of the angle in the formula of flux, we will get a negative flux for the angle of 180 degrees in the outward direction of the bucket.

The flux depends on the surface area. If we cut the base of the bucket and hold it in rain then there will be no surface area that is intersecting by the rainfall. Hence the value of flux will be zero for the no surface area of the bucket.

To know more about the flux, follow the link given below.

https://brainly.com/question/7944455.

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