Answer:
[tex]x=6\\ \\y=-6[/tex]
Step-by-step explanation:
Given the system of two equations:
[tex]\left\{\begin{array}{l}-4x-2y=-12\\ \\4x+8y=-24\end{array}\right.[/tex]
Add these two equations (left side add to left side and right side add to right side):
[tex]-4x-2y+4x+8y=-12+(-24)\\ \\-2y+8y=-12-24\\ \\6y=-36\\ \\y=-6[/tex]
Substitute [tex]y=-6[/tex] into the first equation:
[tex]-4x-2\cdot (-6)=-12\\ \\-4x+12=-12\\ \\-4x=-12-12\\ \\-4x=-24\\ \\x=6[/tex]
