Answer:
800
Explanation:
Focal length of telescope, F = 200cm
Focal length of eyepiece, f = 0.25
The magnifying power of a telescope is given as the ratio of the focal length of the objective of the telescope to the focal length of the lens. Mathematically:
M = F/f
Therefore, when F = 200cm and f = 0.25cm:
M = 200/0.25
M = 800
Answer:
-48cm
Explanation:
the following data are given
focal length of telescope=200cm,
focal length of the eyepiece=0.25cm
From the genera formula used to find the magnifying power which is expressed as
[tex]M=-\frac{fx_{o}}{f_{e}}[1+\frac{f_{e}}{d}][/tex]
where
[tex]f_{e} = focal length of thr eye piece\\ f_{o} =focal length of the telescope\\[/tex]
and d=least distance of distinct vision=25cm
if we substitute values into the formula, we arrive at
[tex]M=-\frac{fx_{o}}{f_{e}}[1+\frac{f_{e}}{d}]\\M=-\frac{200cm}{0.25cm}[1+\frac{0.25cm}{25cm}]\\M=-800cm[1+0.01]\\M=-800cm(1.01)\\M=-808cm \\M=-808cm[/tex]
hence from the answer, we can conclude that the magnifying power of the telescope is -808cm
