Answer:
[tex]5.4\times 10^{-10}C-m[/tex]
Explanation:
We are given that
Charge=[tex]q=0.30 nC=0.3\times 10^{-9} C[/tex]
[tex]1 nC=10^{-9}C[/tex]
Distance between two balls=l=0.90 m
We have to find the magnitude of dipole moment of the two balls.
We know that
Dipole moment=[tex]\mid p\mid=2lq[/tex]
Where q= Charge
l=Distance between two bodies
Using the formula
Magnitude of dipole moment=[tex]\mid P\mid=2\times 0.3\times 10^{-9}\times 0.9=5.4\times 10^{-10}C-m[/tex]
Hence, the magnitude of the dipole moment of the two balls=[tex]5.4\times 10^{-10}C-m[/tex]
