One possible remnant of a supernova, called a neutron star, can have the density of a nucleus, while being the size of a small city. What would be the radius, in kilometers, of a neutron star with a mass 10 times that of the Sun? The radius of the Sun is 7 × 108 m and its mass is 1.99 × 1030 kg.

Respuesta :

Answer:

16.8107912662 km

Explanation:

M = Mass of neutron star = [tex]10\times 1.99\times 10^{30}=1.99\times 10^{31}\ kg[/tex]

R = Radius of neutron star

[tex]\rho[/tex] = Density of a nucleus = [tex]10^{18}\ kg/m^3[/tex] (general value)

Density is given by

[tex]\rho=\dfrac{M}{\dfrac{4}{3}\pi R^3}\\\Rightarrow R^3=\dfrac{M}{\dfrac{4}{3}\pi \rho}\\\Rightarrow R=(\dfrac{1.99\times 10^{31}}{\dfrac{4}{3}\pi\times 10^{18}})^{\dfrac{1}{3}}\\\Rightarrow R=16810.7912662\ m=16.8107912662\ km[/tex]

The radius of the neutron star is 16.8107912662 km

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