A bowling ball rolling at a certain speed has a kinetic energy of 12 J. What will be its new kinetic energy if it now rolls at 3 times the old speed?

Respuesta :

The new kinetic energy of the bowling ball is 108 J,

Answer:

Explanation:

Any object in motion will experience an amount of kinetic energy. So the kinetic energy is directly proportional to the product of mass and square of velocity of the object. In the present case, the bowling ball is experiencing a kinetic energy of 12 J.

So, K.E. = 12 J = [tex]\frac{1}{2}mv^{2}[/tex]

As the ball will be having same mass, so when the velocity is increased three times of old velocity, so new speed will be 3v, where v is the old speed. Then the new kinetic energy will be as below:

New kinetic energy = [tex]\frac{1}{2}m(3v)^{2} = \frac{9}{2}mv^{2}[/tex]

Since we know that [tex]\frac{1}{2}mv^{2}[/tex] = 12 J, substitute this in new kinetic energy equation and we get

New kinetic energy = 9 × 12 J = 108 J.

Hence the new kinetic energy of the bowling ball is 108 J, when the new speed is three times the old speed,

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