Answer:
0.00000103149529075 m²/s
0.0103149529075 stokes
Explanation:
A = [tex]2.4\times 10^-5[/tex]
B = 250 K
C = 140 K
T = 20°C
[tex]\rho[/tex] = Density of water = 998 kg/m³
Viscosity is given by
[tex]\mu=A\times 10^{\dfrac{B}{T-C}}\\\Rightarrow \mu=2.4\times 10^{-5}\times 10^{\dfrac{250}{273.15+20-140}}\\\Rightarrow \mu=0.00102943230017\ Pas[/tex]
Kinematic viscosity is given by
[tex]\nu=\dfrac{\mu}{\rho}\\\Rightarrow \nu=\dfrac{0.00102943230017}{998}\\\Rightarrow \nu=0.00000103149529075\ m^2/s[/tex]
The kinematic viscosity is 0.00000103149529075 m²/s
In BG units [tex]0.00000103149529075\times 10^4=0.0103149529075\ stokes[/tex]
