Answer:
The correct answer is 27 residues.
Explanation:
In an antiparallel beta sheet, there is a repeat for every 7 Angstrom units and the number of residues is two for every repeat. In an antiparallel sheet that exhibits a length of 94.5 Angstrom, the number of residues can be determined by using the following formula:
2 residues per every 7 Angstrom,
Length of the given segment is 94.5 Angstrom
Number of residues in this segment are:
= (number of segments) * (residues per segment)
= (94.5/7) * 2
= 13.5 * 2
= 27 residues.
Thus, the number of residues in this segment is 27.
