Answer:
[tex]3x+13y=14\\\\6x+11y=-2[/tex]
Step-by-step explanation:
We have to check [tex](-4,2)[/tex] satisfies which system.
First System:
[tex]3x+13y=14\\\\6x+11y=-2\\\\Substitute\ (-4,2)\ in\ the\ equations\\\\3\times (-4)+13\times (2)=14\\\\-12+26=14\\\\14=14\\\\6\times (-4)+11\times (2)=-2\\\\-24+22=-2\\\\-2=-2\\\\(-4,2) \ satisfies\ this\ system\ of\ equation.\ Hence\ (-4,2)\ is\ the\ solution\ of\ this\ system.[/tex]
Second System:
[tex]4x+5y=12\\\\8x+3y=-4\\\\Substitute\ (-4,2)\\\\4\times (-4)+5\times (2)=-6\\\\-6\not=12\\\\(-4,2)\ does\ not\ satisfies\ the\ system\ hence\ it\ in\ not\ a\ solution\ of\ this\ system.[/tex]
Third System:
[tex]5x+4y=12\\\\7x+8y=12\\\\Substitute\ (-4,2)\\\\5\times (-4)+4\times (2)=-12\\\\-12\not =12\\\\(-4,2)\ does\ not\ satisfies\ the\ system\ hence\ it\ in\ not\ a\ solution\ of\ this\ system.[/tex]
Fourth System:
[tex]10x+3y=8\\\\17x+6y=10\\\\Substitute\ (-4,2)\\\\10\times (-4)+3\times (2)=-34\\\\-34\not =8\\\\(-4,2)\ does\ not\ satisfies\ the\ system\ hence\ it\ in\ not\ a\ solution\ of\ this\ system.[/tex]
