Respuesta :

calculista

Answer:

The values of x are

[tex]x=-\sqrt{7} , x=\sqrt{7}[/tex]

Step-by-step explanation:

we have

[tex]6x^{2}-42=0[/tex]

Solve for x

Adds 42 both sides

[tex]6x^{2}-42+42=0+42[/tex]

[tex]6x^{2}=42[/tex]

Divide by 6 both sides

[tex]6x^{2}/6=42/6[/tex]

simplify

[tex]x^2=7[/tex]

square root both sides

[tex]x=\pm\sqrt{7}[/tex]

therefore

The values of x are

[tex]x=-\sqrt{7} , x=\sqrt{7}[/tex]

adioabiola

The exact solution for the values of x in the given equation are: +√7 and -√7.

What are the exact values of x in the equation?

From the task content; it follows that the given equation is; 6x² - 42 = 0.

On this note, the evaluation for the values of x can be done as follows;

6x² - 42 = 0

6x² = 42

x² = 7

x = ±√7.

Read more on quadratic equations;

https://brainly.com/question/1214333

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