Answer:
The magnitude of electric field at the center of each ring is 129.96 N/C
Explanation:
As per the question:
The diameter of the ring , d = 10 cm = 0.1 m
Radius, [tex]r = \frac{d}{2} = \frac{0.1}{2} = 0.05\ m[/tex]
Separation between the rings, d = 20.0 cm = 0.20 m
Charge on a ring, q = +20 nC = [tex]20\times 10^{- 9}\ C[/tex]
Now,
The electric field at the center of either ring is given by:
[tex]E = \frac{1}{4\pi \epsilon_{o}}\frac{qd}{(d^{2} + r^{2})^{\frac{3}{2}}}[/tex]
where
[tex]\frac{1}{4\pi \epsilon_{o}} = 9\times 10^{9}[/tex]
Thus
[tex]E = 9\times 10^{9}\times \frac{20\times 10^{- 9}\times 0.20}{(0.20^{2} + 0.05^{2})^{\frac{3}{2}}}[/tex]
E = 129.96 N/C
