Answer:
q= 20 W
Explanation:
Given that
Initial temperature ,T₁ = 2 ºC
Heat gains ,Q = 18 kJ
The final temperature ,T₂ = 20 ºC
time ,t= 15 min
We know that
1 min = 60 s
t= 15 x 60 = 900 s
The average rate of heat transfer is give as
[tex]q=\dfrac{Q}{t}[/tex]
[tex]q=\dfrac{18}{900}\ kW[/tex]
q=0.02 kW
q= 20 W
Therefore the rate of heat transfer will be 20 W.
A soda is initially at 2 °C and 15 minutes later, after gaining 18 kJ, its temperature is 20 °C. The average rate of heat transfer is 20 W.
Heat transfer describes the flow of heat (thermal energy) due to temperature differences and the subsequent temperature distribution and changes.
A soda is initially at 2 °C and 15 minutes later, after gaining 18 kJ, its temperature is 20 °C.
First, we will convert 15 min to seconds using the conversion factor 1 min = 60 s.
15 min × 60 s/1 min = 900 s
Then, we can calculate the average rate of heat transfer using the following expression.
q = Q/t = 18 × 10³ J / 900 s = 20 W
where,
A soda is initially at 2 °C and 15 minutes later, after gaining 18 kJ, its temperature is 20 °C. The average rate of heat transfer is 20 W.
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