A plane flies 1.4hours at 110mph on a bearing of 40degrees.It then turns and flies 1.7hours at the same speed on a bearing of 130degrees.How far is the plane from its starting point?

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Respuesta :

zainsubhani zainsubhani · Answer 1 · 2020-02-05T08:18:13+01:00

Answer:

Distance from starting point= 242.249871 miles

Explanation:

Distance covered on bearing of 40 degree=a= [tex]1.4*110\ mph[/tex]

Distance covered on bearing of 40 degree=a=154 miles

Distance covered on bearing of 130 degree=b=[tex]1.7*110\ mph[/tex]

Distance covered on bearing of 40 degree=b=187 miles

Angle between bearing=[tex]130-40[/tex]

Angle between bearing=90 degree

With the angle of 90 degree, Distance from starting point can be calculated from Pythagoras theorem.

Distance from starting point=[tex]\sqrt{a^2+b^2}[/tex]

Distance from starting point=[tex]\sqrt{154^2+187^2}[/tex]

Distance from starting point= 242.249871 miles

zuu2343 zuu2343 · Answer 2 · 2020-10-15T17:05:05+02:00

Answer:

Distance from starting point= 242.249871 miles

Distance covered on bearing of 40 degree=a=

Distance covered on bearing of 40 degree=a=154 miles

Distance covered on bearing of 130 degree=b=

Distance covered on bearing of 40 degree=b=187 miles

Angle between bearing=

Angle between bearing=90 degree

With the angle of 90 degree, Distance from starting point can be calculated from Pythagoras theorem.

Distance from starting point=

Distance from starting point= 242.249871 miles

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