Respuesta :
Answer:
[tex]d_t=266.918\ miles[/tex] is the total distance of the trip travelled.
[tex]s_{avg}=54.7895\ mph[/tex] is the average speed of the journey
Explanation:
Given:
- duration of first interval, [tex]t_1=3.22\ hr[/tex]
- speed during the first interval, [tex]v_1=65.9\ mph[/tex]
- duration of stoppage, [tex]t_0=42.1\ min=0.7017\ hr[/tex]
- duration of second interval, [tex]t_2=0.95\ hr[/tex]
- speed during second interval, [tex]v_2=57.6\ mph[/tex]
Now the total distance travelled:
[tex]\rm distance=speed\times time[/tex]
[tex]d_t=v_2.t_2+v_1.t_1[/tex]
[tex]d_t=57.6\times 0.95+65.9\times 3.22[/tex]
[tex]d_t=266.918\ miles[/tex]
The average speed:
[tex]\rm speed_{avg}=\frac{total\ distance}{total\ time\ taken}[/tex]
[tex]s_{avg}=\frac{d_t}{(t_0+t_1+t_2)}[/tex]
[tex]s_{avg}=\frac{266.918}{(0.7017+3.22+0.95)}[/tex]
[tex]s_{avg}=54.7895\ mph[/tex]
