Respuesta :
Answer:
The group will need to take a minimum of 5 buses to carry all the people to the trip
Step-by-step explanation:
Given:
Number of 7th grade students going on the trip = 178
Number of chaperones going on the trip = 20
Number of people each bus can hole = 42
To find the number of buses the group will have to take.
Solution:
Let minimum number of buses the group will have to take = [tex]x[/tex]
using unitary method:
If 1 bus can hold = 42 people
Then, [tex]x[/tex] buses can hold = [tex]42x[/tex] people
Total number of people for the trip = [tex]178+20=198[/tex]
The total number of people that can go in [tex]x[/tex] buses must be greater than or equal to 198 in order to carry all the people to the trip.
Thus we have the inequality:
[tex]42x\geq198[/tex]
Solving for [tex]x[/tex]
Dividing both sides by 42.
[tex]\frac{42x}{42}\geq\frac{198}{42}[/tex]
[tex]x\geq4.71\approx 5[/tex] [As number of buses must be in whole number]
Thus, the group will need to take a minimum of 5 buses to carry all the people to the trip.
