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An electronics store makes a profit of $72.00 for every television sold and $90.00 for every computer sold. The manager’s target is to make at least $360.00 a day on sales from televisions and computers. Let x = the number of televisions sold. Let y = the number of computers sold. Which of the following represents three possible solutions to the problem?
A. 72x+90y>360 (5,2),(3,3) and (1,4)
B. 72x+90y<360 (4,0),(2,2) and (1,1)
C. 72x+90y>360 (3,1),(2,2) and (1,0)
D 72x+90y>360 (4,0),(3,3) and (1,4)

Respuesta :

Answer:

Option A, C and D is the three possible solution.

Step-by-step explanation:

Each Television earns $72 and each Computer earns $90.

The manager’s target is to make at least $360.00 a day.

It is not clarified the exact number of Televisions and Computers.

Hence, as per the given condition, [tex]72x + 90y \geq  360\\8x + 10y \geq  40\\4x + 5y \geq  20[/tex].

Now we just need to check the given options, whether they satisfy the above equation, or not.

Except the option B, each inequality indicates a value greater than 360.

Hence, option B can not be the possible solution.

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