Answer:
[tex]\large \boxed{y + 1 = 4(x - 1)}[/tex]
Step-by-step explanation:
The point-slope formula for a straight line is
y - y₁= m(x - x₁)
x₁ = 1; y₁ = -1; m = 4
Substitute the values
[tex]\begin{array}{rcl}y - (-1) & = & 4(x - 1)\\y + 1 & = & 4(x - 1)\\\end{array}\\\text{The equation for the line in point-slope form is $\large \boxed{\mathbf{y + 1 = 4(x - 1)}}$}[/tex]
The figure shows the graph of the equation with slope 4 passing through (1, -1).
