The science club is inflating a model of a hot air balloon. The graph below shows their progress. At what rate is the diameter increasing?

The science club is inflating a model of a hot air balloon The graph below shows their progress At what rate is the diameter increasing class=

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Answer:

12.5 centimeters per minute

Step-by-step explanation:

From the graph, the rate at which the diameter increasing would be inthe units of cm/min

The rate is basically the slope of the line. The slope (m) has formula:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Where

[tex](x_1,y_1)[/tex]  is any point from the graph

and

[tex](x_2,y_2)[/tex]  is another point from the graph

Let's take the origin (0,0) as the first point and (4,50) as the second point. Now lets calculate the slope:

[tex]m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{50-0}{4-0}\\m=\frac{50}{4}\\m=12.5[/tex]

Thus, we can say:

The diameter of the hot air balloon is increasing at a rate of 12.5 centimeters per minute

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