Answer:
{(-2,3), (7,-6)
} -----> y - 15 = -[tex]x^{2}[/tex] + 4x
x + y = 1
{(-5, 8). (3,0)
} ----> y + 12 = [tex]x^{2}[/tex] + x
x + y = 3
{(-2,5),(3,-5)
} -----> y + 5 = [tex]x^{2}[/tex] - 3x
2x + y = 1
{(2, 3), (8,9)} -----> y-17 = [tex]x^{2}[/tex] - 9x
-x + y = 1
Step-by-step explanation:
The simplest way to find the answer is by solving all the equations and finding the value of x and y for each of them.
Solving the equations ->
y + 12 = [tex]x^{2}[/tex] + x
x + y = 3
Substitute y = 3-x from second equation to first and solving the quadratic equation obtained i.e solving [tex]x^{2}[/tex] + 2x -15 = 0 , we get values of x = -5 , 3 and the corresponding values of y by substituting values of x in second equation , y = 8, 0 respectively. So, solution matched = {(-5, 8). (3,0)
}.
Similarly solving other equations using exactly the same method as above we get the following solutions,
For,
y - 15 = [tex]x^{2}[/tex] + 4x
x - y = 1
we don't get any integer solution for this hence it has no match.
For,
y + 5 = [tex]x^{2}[/tex] - 3x
2x + y = 1
we get x = 3,-2 and corresponding y = -5,5
So, solution is {(-2,5),(3,-5)
}
For,
y- 6 = [tex]x^{2}[/tex] – 3x
x + 2y = 2
we again don't get any integer solution for x and y so this has no match.
For,
y-17 = [tex]x^{2}[/tex] - 9x
-x + y = 1
we get x = 2,8 and corresponding y = 3,9
So, {(2, 3), (8,9)} is the solution match.
Lastly for,
y - 15 = -[tex]x^{2}[/tex] + 4x
x + y = 1
we get x = -2,7 and corresponding y = 3,6
So, {(-2,3), (7,-6)} is the solution match.