Consider the following intermediate reactions.
CH4(g)+2O2->CO2(g)+2H2O(g) ΔH1=-802 kJ
2H2O(g)->2H2O(I) ΔH2=-88 kJ
The overall chemical reaction is as follows.
CH4(g)+2O2(g)->CO2(g)+2H2O(I) ΔH2=-890 kJ
What is the correct enthalpy diagram using the Hess law for this system?

Consider the following intermediate reactions CH4g2O2gtCO2g2H2Og ΔH1802 kJ 2H2Oggt2H2OI ΔH288 kJ The overall chemical reaction is as follows CH4g2O2ggtCO2g2H2OI class=
Consider the following intermediate reactions CH4g2O2gtCO2g2H2Og ΔH1802 kJ 2H2Oggt2H2OI ΔH288 kJ The overall chemical reaction is as follows CH4g2O2ggtCO2g2H2OI class=
Consider the following intermediate reactions CH4g2O2gtCO2g2H2Og ΔH1802 kJ 2H2Oggt2H2OI ΔH288 kJ The overall chemical reaction is as follows CH4g2O2ggtCO2g2H2OI class=
Consider the following intermediate reactions CH4g2O2gtCO2g2H2Og ΔH1802 kJ 2H2Oggt2H2OI ΔH288 kJ The overall chemical reaction is as follows CH4g2O2ggtCO2g2H2OI class=

Respuesta :

2.1648 kg of CH4 will generate 119341 KJ of energy.

Explanation:

Write down the values given in the question

CH4(g) +2 O2 → CO2(g) +2 H20 (g)

ΔH1 = - 802 kJ

2 H2O(g)→2 H2O(I)

ΔH2= -88 kJ

The overall chemical reaction is

CH4 (g)+2 O2(g)→CO2(g)+2 H2O (I) ΔH2= -890 kJ

CH4 +2 O2 → CO2 +2 H20

(1mol)+(2mol)→(1mol+2mol)

Methane (CH4) = 16 gm/mol

oxygen (O2) =32 gm/mol

Here 1 mol CH4 ang 2mol of O2 gives 1mol of CO2 and 2 mol of 2 H2O

which generate 882 KJ /mol

Therefore to produce 119341 KJ of energy

119341/882 = 135.3 mol

to produce 119341 KJ of energy, 135.3 mol of CH4 and 270.6 mol of O2 will require

=135.3 *16

=2164.8 gm

=2.1648 kg of CH4

2.1648 kg of CH4 will generate 119341 KJ of energy

Answer:

The answer is A on edge

Explanation:

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