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Dave's sister baked $3$ dozen pies of which a third contained chocolate, a quarter contained marshmallows, a sixth contained cayenne, and one twelfth contained salted soy nuts. What is the smallest possible number of pies that had none of these ingredients?

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SaniShahbaz

Step-by-step explanation:

As Dave's sister baked 3 dozen pies.

So, total number of pies = 3 × 12 = 36

Number of pies = 3×12 = 36

Pies which contained chocolate = 1/3×36 = 12

Pies which contained marshmallows = 1/4×36 = 9

Pies which contained cayenne = 1/6×36 = 6

Pies contained soy nut = 1/12×36 = 3

So,

Pies that had none of these ingredients = 36 - (12+9+6+3)

                                                                   = 36 - 30

                                                                    = 6 pies

So, total 6 pieces are left  that had none of these ingredients.

i.e. 1, 2, 3, 4, 5, 6

Therefore,

  • The largest possible number of pies that had none of thees ingredients = 6 pieces
  • The smallest possible number of pies that had none of thees ingredients = 1 piece

Keywords: smallest possible number

Learn more about word problems regarding numbers from brainly.com/question/1217325

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Athenalsun

She baked 36 pies. Of these

1/3*36=12 contained chocolate

1/4*36=9 contained marshmallows

1/636=6 contained cayenne

1/12*36=3 contained salted soy nuts.

In order to make the number of pies with none of these ingredients as small as possible, Dave's sister should put all of these ingredients in different pies so that only one of the ingredients is in any pie. If she does this, then 12+9+6+3=30 of the pies will have one of these ingredients. The other 6 pies will have none of these ingredients. At least 6 pies have none of these ingredients.

-Alcumus AoPS Staff

Brainliest would be great!!!

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