Answer:
Total cost to paint the room = £73.51
Step-by-step explanation:
Given:
Dimensions of the room = 6.8 m [tex]\times[/tex] 9.2 m
Cost of tin of paint = £11.75
A tin of paint covers an area = 20 [tex]m^2[/tex]
To find the cost of painting the room with two coats of paint.
Solution:
Area of the room = [tex]length\times width=6.8\ m\times 9.2\ m= 62.56\ m^2[/tex]
We will use unitary method to find the amount of paint required for the room.
If [tex]20\ m^2[/tex] of area is covered by 1 tin of paint.
For [tex]1\ m^2[/tex] of area, amount of paint required = [tex]\frac{1}{20}[/tex] of a tin
Then, for [tex]62.56\ m^2[/tex] amount of paint required = [tex]\frac{62.56}{20}=3.128[/tex] tins of paint.
For double coats twice paint must be required.
So, total amount of paint required for painting the room with two coats of paint = [tex]3.128\times 2=6.256[/tex] tins of paints.
Using unitary method to find total cost.
If 1 tin of paint costs = £11.75
6.256 tins of paint will cost = [tex]6.256\times \£11.75=\£73.508\approx\£73.51[/tex]
Total cost to paint the room = £73.51
