Answer:
With the first term is 2 and common difference is 13 then the series is 2,15,28,...
Step-by-step explanation:
Given first term is 2 and common difference is 13.
Arithmetic progression:
[tex]a_{1}=2[/tex] and d=2 [given]
Therefore we can find arithmetic series [tex]a_{1},a_{2},a_{3},...[/tex] with [tex]a_{1}=2[/tex] and d=2
d can be written as [tex]d=a_{2}-a_{1}[/tex]. Therefore we can write [tex]a_{2}[/tex] as below:
[tex]a_{2}=a_{1}+d[/tex]
Now substitute the values [tex]a_{1}=2[/tex] and d=2
[tex]a_{2}=2+13[/tex]
[tex]a_{2}=15[/tex]
Similarly we can find [tex]a_{3}[/tex]
d can be written as [tex]d=a_{3}-a_{2}[/tex]. Therefore we can write [tex]a_{3}[/tex] as below:
[tex]a_{3}=a_{2}+d[/tex]
[tex]a_{3}=15+13[/tex]
[tex]a_{3}=28[/tex]
and so on.
Therefore the series is 2,15,28,...
