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1. A projectile is launched into the air with an initial speed of vi = 40 m/s at a launch
angle of 20° above the horizontal. The projectile lands on the ground 5.0 seconds
later.
Neglecting air resistance, calculate the projectile's range and draw projectile
path

Respuesta :

rafaleo84

Answer:

range = x = 188 [m]

Explanation:

First we must find the velocity component on the horizontal axis or x-axis

[tex](v_{x})_{0} = 40*cos(20) \\(v_{x})_{0} = 37.58[m/s]\\[/tex]

Then using the kinematic expression that relates velocity with time, we can find the range of the projectile or the distance x.

[tex]x=(v_{x} )_{0}*t\\ x=37.58*5\\x=188[m][/tex]

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